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MCAT Question of the Day
Q:
A simple pendulum has a mass M attached to its end. Its period of oscillation on Earth is T. The pendulum is taken to a different planet where the gravity is one fourth of Earth's. Also, the length of the string doubles, and another mass M (thus there is a total mass of 2M on the pendulum) is placed on the pendulum. What is the ratio of the period of oscillation on Earth to the period of oscillation on this new planet?
A
1 : √8
B
1: 2
C
1 : √2
D
Cannot be determined with the information provided.
Periodic Motion
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