MCAT Question of the Day
    •

    Q:

    		 A 20.0 eV photon collides with a hydrogen atom which was initially in ground state (with an ionization potential of 13.6 eV). Calculate the kinetic energy of the ejected electron.

    		 

    A

    		 6.4 eV

    B

    		 13.6 eV

    C

    		 20.0 eV

    D

    		 33.6 eV



    Atomic & Electronic Structure | Quantitative Skills |
    Subscribe


    Is Your Score Stuck?

    We can teach you how to crush the MCAT!

    Learn More