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MCAT Question of the Day
Q:
The molecule below is developed in the laboratory. A separate molecule is constructed where the NO
2
group moves to the adjacent carbon atom. This alcohol is then deprotonated. The pk
a
would be expected to:
A
Increase because the modification allows for better resonance to stabilize the negative charge on the conjugate base
B
Decrease because the modification allows for better resonance to stabilize the negative charge on the conjugate base
C
Increase because the modification eliminates the resonance stabilization of the negative charge on the conjugate base
D
Decrease because the modification eliminates the resonance stabilization of the negative charge on the conjugate base
Acid/Base Equilibria
|
Alcohols
|
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