MCAT Question of the Day
    •

    Q:

    		 Lead chloride dissolves in aqueous solution in the following fashion: PbCl2(s) → Pb2+(aq) + 2Cl-(aq). An experiment is performed by adding 100 g of solid lead chloride to 500 mL of water; 85 g of lead chloride are found to be undissolved at the end of the experiment. Which of the following is the solubility product for the reaction? Assume the molar weight of lead chloride is 300 g.
    		 

    A

    		 0.004

    B

    		 0.04

    C

    		 0.24

    D

    		 0.001



    Solutions | Quantitative Skills |
    Subscribe


    Is Your Score Stuck?

    We can teach you how to crush the MCAT!

    Learn More