MCAT Question of the Day
    •

    Q:

    		 Given the potentials of the following half-reactions, how would the net reaction proceed if set up to run as a spontaneous reaction?

    Al3+ + 3e- → AlE° = -1.66 V
    Fe3+ + 3e- → FeE° = -0.04 V
    		 

    A

    		 Al3+ + Fe3+ → Al + Fe

    B

    		 Al3+ + Fe → Al + Fe3+

    C

    		 Al + Fe3+ → Fe + Al3+

    D

    		 Al + Fe → Al3+ + Fe3+



    Thermochemistry | Quantitative Skills |
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